Question

Predict the position of the element in the periodic table satisfying the electronic configuration $(n-1)d^1{ns}^2$ for $n=4$.

Answer 1

Here outer most electron enters into the $3d$ hence the element belongs to $d-block$, number of group for $d-block$ element= no. of electrons in (n-1)orbital + no. of electrons in n orbital=2+1=3 hence, the element belongs to 3rd group. Here principal quantum number is equal to the period of the element hence the element belongs to 4th period.