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B
CH3CH(OH)C6H5
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C
CH3CH(OH)C2H5
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D
(CH3)2C(OH)C6H5
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Solution
The correct option is D(CH3)2C(OH)C6H5 Acetic acid forms acetylehloride on treating with PCl5 which on treating with benzene in presence anhydrous AlCl3 undergoes Freedel craft reaction to form acetophenone. Acetophenone reacts with methyl magnesium bromide to form (CH3)2C(OH)C6H5 as shown above.