Predict the product C obtained in the following reaction of but-1-yne.
$C H_{3} C H_{2} - C \equiv C H + H C l \to B H I - - \to C$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
This reaction occurs according to Markovnikov's rule which states that when an unsymmetrical alkene undergo hydrohalogenation, the negative part of the addendum (adding molecule) gets attached to that doubly bonded C which posses lesser number of hydrogen atoms.

By markovnikov's rule, the $C l^{-}$ gets adds to the carbon which has lesser number of hydrogen atom and forms a alkene.
Formed alkene reacts with HI molecule to undergo markovnikov's addition. Here, the carbocation formed is an tertiary carbocation which is more stable. Thus the major product is (c)

Suggest Corrections

Similar questions

C H_{3} C H_{2} - C \equiv C H + H C l \to B H I - - \to C

C

C H_{3} C H_{2} - C \equiv C H + H C l ⟶ B H I - - \to C

Predict the product C obtained in the following reaction of

$C H_{3} C H_{2} - C \equiv C H + H C l \to B H I - - \to C$

^{'} C^{'}

1

C H_{3} - C H_{2} - C \equiv C H + H C l ⟶ B H I - -------- \to C

H C l

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program