Predict the product of electrolysis when an aqueous solution of $A g {N O}_{3}$ with silver electrodes.

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Solution

$A g N O_{3} ⟶ {A g}^{+} + {N O_{3}}^{-}$
$H_{2} O ⇌ H^{+} + {O H}^{-}$
At cathod:- ${A g}^{+}$ is preferably discharged as compared to $H^{+}$ as its reduction potential is higher.
${A g}^{+} + e^{-} ⟶ A g$
At anode:- Silver electrode dissolves to produce ${A g}^{+}$ .
$A g ⟶ {A g}^{+} + e^{-}$

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