Question

Predict the reaction mechanism of (I) and (II).

• A. I- $S_{N}2$ and II - $S_{N}1$
• B. I- $E2$ and II - $E1$
• C. I- $E2$ and II - $S_{N}1$
• D. I- $S_{N}2$ and II - $E1cB$

Answer 1

The correct option is B I- $E2$ and II - $E1$

Both reaction occurs by heating so it favours elimination reaction.
In (I), we have primary alkyl halide and $KOH$ will act as strong base so it will undergo E2 elimination.

In (II), we have tertiary alkyl halide which is sterically hindered and the $H_{2}O$ is a poor base so it will undergo E1 elimination via a stable tertiary carbocation intermediate.