Question 49

Predict the shapes of the following molecules on the basis of hybridisation.

$B C l_{3}, C H_{4}, C O_{2}, N H_{3}$

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Solution

In $B C l_{3}$ , the geometry is trigonal planar is due to $s p^{2}$ hybridisation.

The shape of $C H_{4}$ is tetrahedral due to $s p^{3}$ hybridisation.

$C O_{2}$ show linear shape because of sp hybridisation.

The geometry of $N H_{3}$ is pyramidal shape and has $s p^{3}$ hybridisation.

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