The correct option is
B 37Square root of 1368 using vilokamam method
⇒ It's unit digit is 9, therefore, the unit digit of the square root will be 3 or 7.
⇒ Ignoring the last two digits(unit & tens digits) we get 13
⇒ The greatest No. whose square is less than or equal to 13 is 3.
⇒ Adjusting above obtained then unit digits 3 or 7 to the right of 3, we get two numbers 33 & 37
⇒ The unique number with unit digit 5 which lies between 33 & 37 is 35.
(35)2=(3×4)×25=
(35)2=(3×4).2=1225
by Ekadhikena sutra
Since 1369>1225, therefore, the required root is ⇒37.
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