Predict the value of $^{'} x^{'}$ in ${C o}_{2} {(C O)}_{x}$ and ${M n}_{x} {(C O)}_{10}$ respectively: ( follow EAN rule)

9, 4

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8, 2

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10, 2

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6,3

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Solution

The correct option is B 8, 2
For EAN to follow each atom must posses either 36, 54, or 86 $e^{- 1}$
${C o}_{2} {(C O)}_{x} \Rightarrow C O = {2 e}^{-} d e n e r l i g a n g 2 \times 27 + 2 x = 86 2 x = 32 x = \frac{32}{2} = 16 T h i s v a l u e f o r 2 C O a t o m F o r o n e C O = \frac{16}{2} = 8 x = 8 {M n}_{x} {(C O)}_{10} 25 \times x + 10 \times 2 = 86 25 x = 86 - 20 x = \frac{66}{25} = 2.64 S o 2.64 ≃ 2$

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