Predict whether the following reaction will occur spontaneously or not- Co2- - Sn- Co - Sn2- ECo-Co2- - 0-277 volt and ESn- Sn2- - 0-136 volt-

In the given reaction, Co^2+ is getting reduced and Sn is getting oxidized; E^0_cell = reduction potentail of cathode reduction potential of anode ...

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Standard VII

Chemistry

EMF

Predict wheth...

Question

Predict whether the following reaction will occur spontaneously or not:
$C o^{2 +} + S n \to C o + S n^{2 +}$
$E_{C o / C o^{2}}^{\circ} = 0.277 v o l t$ and $E_{S n / S n^{2 +}}^{\circ} = 0.136 v o l t$ .

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Solution

in the given reaction,
$C o^{2 +}$ is getting reduced and Sn is getting oxidized;
$E_{c e l l}^{0}$ = reduction potentail of cathode - reduction potential of anode
$E_{c e l l}^{0}$ = $0.277 - 0.136$
$E_{c e l l}^{0}$ = positive
hence, the reaction is sponateous.

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Predict whether the following reaction will occur spontaneously or not:Co2++Sn→Co+Sn2+E∘Co/Co2=0.277 volt and E∘Sn/Sn2+=0.136 volt.

in the given reaction,Co2+ is getting reduced and Sn is getting oxidized;E0cell = reduction potentail of cathode - reduction potential of anodeE0cell= 0.277−0.136E0cell= positivehence, the reaction is sponateous.

Predict whether the following reaction will occur spontaneously or not:
$C o^{2 +} + S n \to C o + S n^{2 +}$
$E_{C o / C o^{2}}^{\circ} = 0.277 v o l t$ and $E_{S n / S n^{2 +}}^{\circ} = 0.136 v o l t$ .

in the given reaction,
$C o^{2 +}$ is getting reduced and Sn is getting oxidized;
$E_{c e l l}^{0}$ = reduction potentail of cathode - reduction potential of anode
$E_{c e l l}^{0}$ = $0.277 - 0.136$
$E_{c e l l}^{0}$ = positive
hence, the reaction is sponateous.