The correct option is D 300
Let the cost of the first book be x rupees.
Then, the cost of the second book = (x + 100) rupees
And the cost of the third book = (x + 100 + 300) = (x + 400) rupees
Given: Sum of the cost of all three books = ₹1100
x + (x + 100) + (x + 400) = 1100
⇒ x + x + 100 + x + 400 = 1100
⇒ 3x + 500 = 1100
Clearly, we have to try with some big numbers here.
If x = 100, 3x+500=3×100+500=300+500=800
If x = 200, 3x+500=3×200+500=600+500=1100
Therefore, if x = 200, LHS = RHS.
Hence, the cost of the second book = x + 100 = 200 + 100 = ₹300