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Question

Presence of recessive trait is 16%. The frequency of dominant allele in population is

A
0.6
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B
0.32
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C
0.84
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D
0.92
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Solution

The correct option is A 0.6
Let's start with the basic Hardy-Weinberg equations first.
p+q=1 and p^2+2pq+q^2=1

With "p" being the dominant allele and "q" being the recessive allele

We know that 16% (or 0.16) show the recessive trait. This means that the fraction of the population with the recessive trait,
q^2 is 0.16

With the value for q^2, q can be calculated. What follows is that q=0.4

With this knowledge "p" can be calculated, 1q=p, which results in "p" being 0.6

This 0.6 is the frequency at which the dominant allele is present in the population.

So, the correct answer is '0.6'.

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