Presence of which regent will affect the reversibility of the following reaction, and change it to a irreversible reaction.
$C H_{4} + I_{2} h v ⇌ Reversible C H_{3} - I + H I$

Concentrated $H I O_{3}$

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Dilute

H N O_{2}

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HOCI

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Liquid

N H_{3}

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Solution

The correct option is A
Concentrated $H I O_{3}$

Iodination is very slow and a reversible reaction.
Formed $H I$ in product side is powerful reducing agent, it will reduced alklyl iodide to $I_{2}$ .
The reaction can be irreversible in the presence of strong oxidising agent like $c o n c . H N O_{3} o r c o n c . H I O_{3} .$ It will oxidise the $H I$ to $I_{2}$ and make the reaction irreversible.

$C H_{4} + I_{2} ⇌ C H_{3} - I + H I$
$H I O_{3} + 5 H I \to 3 I_{2} + 3 H_{2} O$

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