Present ages of Sita and Geeta are in the ratio 4 : 5. Eight years from now the ratio of their ages will be 5 : 6. Find their present ages. [4 MARKS]
Concept: 2 Marks
Application: 2 Marks
Let the present ages of Sita and Geeta be 4x years and 5x years respectively.
After eight years. Sita’s age
=(4x+8) years;
After eight years, Geeta’s age
=(5x+8) years.
Therefore, the ratio of their ages after eight years
=4x+85x+8=56
Cross-multiplication gives
6(4x+8)=5(5x+8)
24x+48=25x+40
24x+48–40=25x
24x+8=25x
8=25x–24x
8=x
Therefore, Sita’s present age
=4x=4×8=32 years
Geeta’s present age
=5x=5×8=40 years