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Question

Present the data given in the table below in the form of a Histogram :
Mid-points : 115 125 135 145 155 165 175 185 195
Frequency : 6 25 48 72 116 60 38 22 3

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Solution

The two-dimensional diagrams that depict the frequency distribution of a continuous series by the means of rectangles are called histograms.
In order to construct a histogram, we first require the class intervals corresponding to the various mid-points, which is calculated using the following formula.

The value obtained is then added to the mid point to obtain the upper limit and subtracted from the mid-point to obtain the lower limit.

For the given data, the class interval is calculated by the following value of adjustment.
Value of Adjustment = 125 -115 2 = 5

Thus, we add and subtract 5 to each mid-point to obtain the class interval.

For instance:

The lower limit of first class = 115 – 5 = 110

Upper limit of first class = 115 + 5 = 120.

Thus, the first class interval is (110-120). Similarly, we can calculate the remaining class intervals.

Mid-points Class Interval Frequency
115
125
135
145
155
165
175
185
195
110 − 120
120 − 130
130 − 140
140 − 150
150 − 160
160 − 170
170 − 180
180 − 190
190 − 200
6
25
48
72
116
60
38
22
3


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