Present the following as an ordinary grouped frequency table- - Marks below 10 20 30 40 50 60- Number of students 5 12 32 40 45 48- -

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Standard IX

Mathematics

Grouped Frequency Table

Present the f...

Question

Present the following as an ordinary grouped frequency table:
$\begin{matrix} Marks (below) & 10 & 20 & 30 & 40 & 50 & 60 (Number of students) & 5 & 12 & 32 & 40 & 45 & 48 \end{matrix}$

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Solution

Sol:

Marks Number of students
(Cumulative Frequency)
Class Intervals Frequency

10 5 0-10 5

20 12 10-20 12-5=7

30 32 20-30 32-12=20

40 40 30-40 40-32=8

50 45 40-50 45-40=5

60 48 50-60 48-45=3

Total 48

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Similar questions

Present the following as an ordinary grouped frequency table:
$\begin{matrix} Marks (below) & 10 & 20 & 30 & 40 & 50 & 60 (Number of students) & 5 & 12 & 32 & 40 & 45 & 48 \end{matrix}$

Q. Present the following as an ordinary grouped frequency table:

Marks (below)	10	20	30	40	50	60
Number of students	5	12	32	40	45	48

Draw a frequency polygon for the following frequency distribution:
$\begin{matrix} Class interval & 1 - 10 & 11 - 20 & 21 - 30 & 31 - 40 & 41 - 50 & 51 - 60 Frequency & 8 & 3 & 6 & 12 & 2 & 7 \end{matrix}$

If the cumulative frequency for the class interval (50-60) is 92, then find x

$\begin{matrix} Class Interval & 0 - 10 & 10 - 20 & 20 - 30 & 30 - 40 & 40 - 50 & 50 - 60 Frequency & 12 & 20 & x & 18 & 10 & 6 \end{matrix}$

Q. The class-width of the intervals in the given grouped frequency disribution table is:

Class interval	Frequency
0-10	2
10-20	10
20-30	21
30-40	19
40-50	7
50-60	1
Total	60

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Marks	Number of students (Cumulative Frequency)	Class Intervals	Frequency
10	5	0-10	5
20	12	10-20	12-5=7
30	32	20-30	32-12=20
40	40	30-40	40-32=8
50	45	40-50	45-40=5
60	48	50-60	48-45=3
		Total	48

Present the following as an ordinary grouped frequency table: Marks (below)102030405060(Number of students)51232404548

Sol: Marks Number of students (Cumulative Frequency) Class Intervals Frequency 10 5 0-10 5 20 12 10-20 12-5=7 30 32 20-30 32-12=20 40 40 30-40 40-32=8 50 45 40-50 45-40=5 60 48 50-60 48-45=3 Total 48

Present the following as an ordinary grouped frequency table:
$\begin{matrix} Marks (below) & 10 & 20 & 30 & 40 & 50 & 60 (Number of students) & 5 & 12 & 32 & 40 & 45 & 48 \end{matrix}$

Sol:

Marks Number of students
(Cumulative Frequency)
Class Intervals Frequency

10 5 0-10 5

20 12 10-20 12-5=7

30 32 20-30 32-12=20

40 40 30-40 40-32=8

50 45 40-50 45-40=5

60 48 50-60 48-45=3

Total 48