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Question

Present the following as an ordinary grouped frequency table:
Marks (below)102030405060(Number of students)51232404548


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Solution

Sol:

Marks Number of students

(Cumulative Frequency)

Class Intervals Frequency
10 5 0-10 5
20 12 10-20 12-5=7
30 32 20-30 32-12=20
40 40 30-40 40-32=8
50 45 40-50 45-40=5
60 48 50-60 48-45=3
Total 48

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