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Question

Pressure exerted by 1 mole of methane in a 0.25 litre container at 300K using vander Waal's equation (given a = 2.253 atml2mol2, b = 0.0428 lit mol1) is
  1. 152.51 atm
  2. 190.52 atm
  3. 82.82 atm
  4. 70.52 atm


Solution

The correct option is C 82.82 atm

(P+n2aV2)(V - nb) = nRT
(P+2.2530.25×0.25)(0.25 - 0.0428) = 0.0821 × 300
or (P + 36.048)(0.2072) = 24.63
P + 36.08 = 118.87
P = 82.82 atm

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