Question

Pressure exerted by one mole of an ideal gas kept in vessel of '$V$' L having root mean square molecule '$V$' and '$m$' mass of each molecule is correctly given by the equation?

• A. $P=$ $\frac{1}{2}$$\frac{N}{V}$mv${}^2$
• B. $P=$ $\frac{1}{3}$$\frac{N}{V}$mv${}^2$
• C. $P=$ $\frac{2}{3}$$\frac{N}{V}$mv${}^2$
• D. $P=$ $\frac{3}{2}$$\frac{N}{V}$mv${}^2$

Answer 1

The correct option is B $P=$ $\frac{1}{3}$$\frac{N}{V}$mv${}^2$

According to ideal gas and kinetic theory of gases, pressure exerted by one mole of ideal gas in a vessel of volume $V$, having mean square molecule ${}^{\prime }{V}^{\prime }$ and ${}^{\prime }{m}^{\prime }$ mass of each molecule is given by

$P=\frac{1}{3}\frac{N}{V}{mv}^2$