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Question

Pressure inside two soap bubbles are 1.01 and 1.02 atmospheres. Ratio between their volumes is

A

102 : 101

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B

(102)3 : (101)3

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C

8 : 1

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D

2 : 1

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Solution

The correct option is D. 8 : 1.

Given,

Outside pressure = 1 atm

Pressure inside first bubble = 1.01 atm

Pressure inside second bubble = 1.02 atm

Excess pressure P1 = 1.01 - 1 = 0.01 atm

Excess pressure P2 = 1.02 - 1 = 0.02 atm

We know that, P=4Tr, where T is the surface tension and R is the radius of the bubble.

P1rr1Pr1r2=P2P1=0.020.01=21

Since V=43πr3

V1V2=r1r23=213=81


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