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Question

Pressure of 10 moles of an ideal gas is changed from 2 atm to 1 atm against constant external pressure without change in temperature. If surrounding temperature (300 K) and pressure (1 atm) always remains constant then calculate total entropy change (ΔSsystem + ΔSsurrounding) for given process. [Given: ℓn2 = 0.70 amd R=8.0 J/mol/K]


A

56 J/K

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B

14 J/K

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C

16 J/K

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D

None of these

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Solution

The correct option is C

16 J/K


ΔSsystem = nRlnp1p2 = 10 × 8ln21 = 56J/K

ΔSsurrounding = qT

ΔU = q + w, w = Pext(V2 V1)

q Pext(nRTp2 nRTp1) = nRT(Pextp2 Pextp1)

= 10 × 8 × T(1 12)

ΔSsurrounding = qT 40J;

ΔSsystem + ΔSsurr = 56 40 16J/K


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