Question

Pressure remaining the same, the volume of a given mass of an ideal gas increases for every degree centigrade rise in temperature by definite fraction of its volume at

• A.
• B. Its critical temperature
• C. Absolute zero
• D. Its Boyle temperature

Answer 1

The correct option is A

$V_t=V_e(1+{\alpha }_{v}t)$

$\therefore (V_2-V_1)=\Delta V=V_O\alpha (t_2-t_1)$

if $t_2-t_1=1^{\circ }$ then $\Delta V=\alpha V_O$

For every $1^{\circ }C$ increase in tempreture, the volume of a given mass of an ideal gas increases by a definite fraction $\frac{1}{273.15}of{V}_0$.

Here $V_O$ is volume at $0^{\circ }C$ temperature.