Pressure-temperature relationship for an ideal gas undergoing adiabatic change is $γ = \frac{C_{p}}{C_{v}}$

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Solution

The correct option is D

$P V^{γ} = c o n s t a n t \Rightarrow P {(\frac{R T}{P})}^{γ} = c o n s t a n t$

$\Rightarrow P^{1 - γ} T^{γ} = c o n s t a n t$ .

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Similar questions

Q. Pressure-temperature relationship for an ideal gas undergoing adiabatic change is:

γ = C_{p} / C_{v}

Q. During an adiabatic process, if the pressure of the ideal gas is proportional to the cube of its temperature, the ratio

γ = \frac{C_{p}}{C_{v}}

is
(

C_{p} =

Specific heat at constant pressure ;

C_{v} =

Specific heat at constant volume)

Q. During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio

\frac{C_{p}}{C_{v}} = γ

for the gas is

One mole of an ideal gas with $\frac{C_{p}}{C_{v}} = γ$ at absolute temperature $T_{1}$ is adiabatically compressed from an initial pressure
$P_{1}$ to a final pressure $P_{2}$ . The resulting temperature $T_{2}$ of the gas is given by

Q. During an adiabatic process, the pressure of a gas is proportional to the cube of its adiabatic temperature. The value of

\frac{C_{p}}{C_{v}}

for that gas is :

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Pressure-temperature relationship for an ideal gas undergoing adiabatic change is γ=CpCv

The correct option is D PVγ=constant⇒P(RTP)γ=constant ⇒P1−γTγ=constant.

Pressure-temperature relationship for an ideal gas undergoing adiabatic change is $γ = \frac{C_{p}}{C_{v}}$

The correct option is D

$P V^{γ} = c o n s t a n t \Rightarrow P {(\frac{R T}{P})}^{γ} = c o n s t a n t$

$\Rightarrow P^{1 - γ} T^{γ} = c o n s t a n t$ .