Pressure varies inversely with volume while temperatures varies directly with volume. At a time, Volume $= 50 m^{3}$ , Temperature $= 25^{o}$ K and Pressure $= 1$ atmosphere. If the volume is increased to $200 m^{3}$ , then find the temperature in $^{o}$ K

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Solution

$P α \frac{T}{V} \Rightarrow \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
Hence $\frac{1 \times 50}{25} = \frac{1 \times 200}{T_{2}} \Rightarrow T_{2} = 100 k$

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