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Question

Pressure versus density graph of an ideal gas is shown in figure. Choose the correct option.
1144095_3c30bb6f819f4bba9a35a853fd5e1478.JPG

A
During the process AB work done by the gas is positive
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B
During the process AB work done by the gas is negative
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C
During the process BC internal energy of the gas is increasing
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D
None of the above
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Solution

The correct option is A During the process AB work done by the gas is positive
Solution
We know that,
f(density = nMV [Mass = moles × Molar mass](Volume)
so, V=nMf ___ (i)
In process AB f = constant,
Also, V constant [By eq - (i)]
so, ΔW=ΔPU
As ΔP=+ve [P is increasing from A to B]
ΔW=ΔPV=VΔP+PΔV=VΔP to
ΔW=VΔP=+ve
In process B-C, we have
PMRT=fT=PMRP
As Pf constant, T=(Pf)MR constant
Internal energy (nCVT) will remain
same -
Option - A is correct.


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