Question

Pressure versus temperature graph of an ideal gas at constant volume V is shown by the straight line A. Now mass of the gas is doubled and volume is halved, then the corresponding pressure versus temperature graph will be shown by the line.

• A. A
• B. B
• C. C
• D. None of these

Answer 1

The correct option is B B

(Refer to Image)

Pressure-temperature graph

Volume= $V$

According to Charle's and Boyle's law,

$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

or, $\frac{PV}{T}=\frac{2P\lambda V/2}{T_1}$

or, $T_1=T$

This is shown by the line $B$ .