Question

Primary circuit of potentio meter is as shown in the diagram find potential gradient.

Answer 1

Given,

$V=2v,R_{AB}=10\Omega ,L=10m,,R_1=1\Omega ,R_2=20\Omega$

Current through the circuit =$V\ast R$= $\frac{2}{31}$

So the PD across AB is $\frac{2}{31}\times 10=0.64$

Where $PD=\frac{v}{R}\times l$

$R=R_1+R_2+R_{AB}$

Therefore, The potential gradient is=$V\ast L$= $\frac{0.64}{10}=0.064v/m$