wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Primitive of f(x)=x.2In(x2+1) with respect to x is

A
2In(x2+1)(x2+1)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(x2+1)2In(x2+1)In2+1+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(x2+1)In2+12(In2+1)+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(x2+1)In22(In2+1)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C (x2+1)In2+12(In2+1)+C
I=x2In(x2+1)dx let x2+1=t;xdx=dt2
Hence I=122Intdt=12tIn2dt=12.tIn2+1In2+1+C=12.(x2+1)In2+1In2+1+C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon