Principle $= R s . 1000$
Rate of simple interest per year $= 10 %$
Time $= 3$ years
Amount $=$ ?

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Solution

Given, Principle $= R s . 1000$ and rate of simple interest per year $= 10 %$ and time $= 3$ years.
In $3$ years total interest is $\frac{1000 \times 10 \times 3}{100} = 300$ .
So in $3$ years total amount is $1, 000 + 300 = 1, 300$ .

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Similar questions

Find the simple interest, when:
(i) Principal $= R s .2000$ , Rate of Interest $= 5 %$ per annum and Time $= 5$ years.
(ii) Principal $= R s .500$ , Rate of Interest $= 12.5 %$ per annum and Time $= 4$ years.
(iii) Principal $= R s .4500$ , Rate of Interest $= 4 %$ per annum and Time $= 6$ months.
(iv) Principal $= R s .12000$ , Rate of Interest $= 18 %$ per annum and Time $= 4$ months.
(v) Principal $= R s .1000$ , Rate of Interest $= 10 %$ per annum and Time $= 73$ days.

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\frac{100 \times SI}{P \times T}

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What is the rate of simple interest per annum if, Rs 1000 amounts to Rs 1900 in 3 years?

Q. A certain principal amounts to

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6

years at the simple rate of interest

4 %

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Principle =Rs.1000Rate of simple interest per year =10%Time =3yearsAmount =?

Given, Principle =Rs.1000 and rate of simple interest per year =10% and time =3years.In 3 years total interest is 1000×10×3100=300.So in 3 years total amount is 1,000+300=1,300.

Principle $= R s . 1000$
Rate of simple interest per year $= 10 %$
Time $= 3$ years
Amount $=$ ?

Given, Principle $= R s . 1000$ and rate of simple interest per year $= 10 %$ and time $= 3$ years.
In $3$ years total interest is $\frac{1000 \times 10 \times 3}{100} = 300$ .
So in $3$ years total amount is $1, 000 + 300 = 1, 300$ .