Prism angle and refractive index respectively for a prism are 60∘ and 1.414. Angle of minimum deviation will be
A
15∘
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B
30∘
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C
45∘
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D
60∘
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Solution
The correct option is B30∘ n=sin(A+δm)2sin30∘ where n is the refractive index, δm is the angle of minimum deviation, A is the prism angle ⇒1.414=sin(60+δm)2sin30∘⇒sin(60+δm2)=0.707=sin45∘⇒60+δm2=45∘⇒δm=30∘