Given that, radius of circle (r) = 14 cm and length of rectangle (l) = 24 cm
∴ Length of the wire = Circumference of the circle = 2πr=2×227×14=88 cm
Let b be the width of rectangle.
Since, the wire is rebent in the form of rectangle.
∴ Perimeter of rectangle = Circumference of the cirle
⇒2(24+b)=88
⇒24+b=44⇒b=44−24
⇒b=20 cm
Area of circle =πr2=227×(14)2=616 cm2
∵ Area of rectangle =l×b=24×20=480 cm2
Hence, the circle encloses more area than rectangle.