1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Probability is 0.45 that a dealer will sell at least 20 television sets during a day, and the probability is 0.74 that he will sell less that 24 televisions. The probability that he will sell 20,21,22 or 23 televisions during the day, is

A
0.19
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.32
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
0.21
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
None of these
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B 0.19Let A be the event that the sale is at least 20 televisions, i.e. 20,21,22,...and B be the event that sale is less than 24 i.e. 0.1.2.3...23.Then A∩B will denote the sale of 20,21,22 and 23 televisions,We are given P(A)=0.45 and P(B)=0.74.It is required to find P(A∩B).Also P(A∪B)=P( sale of 0,1,2,3,...,20,21,22,23 televisions)=P(S)=1From addition rule, required probability is P(A∩B)=P(A)+P(B)−P(A∪B)=0.45+0.74−1=0.19

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program