Question

Probability of getting $3$ heads and $3$ tails in tossing a coin $3$ times is

• A. $\frac{1}{8}$
• B. $\frac{1}{4}$
• C. $\frac{3}{8}$
• D. $\frac{1}{2}$

Answer 1

The correct option is B $\frac{1}{4}$

The possible outcomes are :
$\{HHH,TTT,HHT,HTH,THH,TTH,THT,HTT\}$
Number of total possible outcomes = $8$
Number of favourable outcomes = $2$ {i.e., $TTT$ and $HHH$}
Probability of getting $3$ heads and $3$ tails $P=\frac{\text{Number of favourable outcomes}}{\text{Number of total possible outcomes}}=$ $\frac{2}{8}$$=$$\frac{1}{4}$