Probability that a random chosen three digit number has exactly 3 factors is

\frac{2}{225}

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\frac{7}{900}

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\frac{1}{300}

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\frac{4}{900}

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Solution

The correct option is B $\frac{7}{900}$
A number has exactly 3 factors if the number is square of a prime number ,
Squares of 11,13,17,19,23,29,31 are 3 digit numbers
=> Required probability = $\frac{7}{900}$

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Probability that a random chosen three digit number has exactly 3 factors is

The correct option is B 7900A number has exactly 3 factors if the number is square of a prime number , Squares of 11,13,17,19,23,29,31 are 3 digit numbers => Required probability =7900

The correct option is B $\frac{7}{900}$
A number has exactly 3 factors if the number is square of a prime number ,
Squares of 11,13,17,19,23,29,31 are 3 digit numbers
=> Required probability = $\frac{7}{900}$