Product (A) and (B) respectively in the above reaction are:
A
Ph−O||C−NH−CH3,Ph−O||C−NH−CH3
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B
CH3−O||C−NH−Ph,CH3−O||C−NH−Ph
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C
Ph−O||C−NH−CH3,CH3−O||C−NH−Ph
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D
CH3−O||C−NH−Ph,Ph−O||C−NH−CH3
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Solution
The correct option is DPh−O||C−NH−CH3,CH3−O||C−NH−Ph As refer to IMAGE 01, in this reaction group anti to −OH group will migrate. This is called as Beckmann rearrangement of oximes to give amide. Refer to IMAGE 02, Same mechanism as that in (A). Here antigroup to −OH group is −Ph, so Ph will migrate, rest mechanism is same.