The correct option is A Ph CH_2 Br CBrCL_3 Br+.CCl_3 PhCH_3 CHCl_3+PhCH_2. PhCH_2Br+.CCl_3 The use of light suggests free radical mechanism hence ...

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Cross Aldol Condensation

Product A is ...

Question

Product A is :

P h - C H_{2} - B r

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P h - C H - B r_{2}

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P h - C C l B r_{2}

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P h - C H_{2} - C C l B r_{2}

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Solution

The correct option is A $P h - C H_{2} - B r$
$C B r C L_{3} h v - \to B r + . C C l_{3}$

$P h C H_{3} . C C l_{3} - -- \to C H C l_{3} + P h C H_{2} . C B r C l_{3} - --- \to P h C H_{2} B r + . C C l_{3}$

The use of light suggests free radical mechanism hence methane derivative will undergohomolytic fission. Since $C - B r$ bond is weaker than the $C - C l$ bond hence former will be broken. Attack by the free radical on toluene occurs at methyl group and not in the ring because $C - H$ bond in Me is weaker than that of ring hydrogen atom and the benzyl free radical is more stable than aryl free raadical.

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Ph - C \equiv N H_{3} O^{+} - --------- \to Partial Hydrolysis (A) {Br}_{2} + KOH - ---- \to (B)

Product (A) is :

P h - C H = C H - C H_{2} B r H O H - -- \to [X]

[X]

P h - C H_{2} - C | H O H - C H_{3} K - \to C_{2} H_{5} B r - ---- \to (A)

(A)

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