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B
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C
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D
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Solution
The correct option is C First reaction is retro aldol reaction. It is a reverse of aldol reaction.
Initially the strong base will abstract the acidic proton from the OH and forms a keto group which leads to C−C bond breakage to form carbanion followed by proton abstraction.
Formed acetaldehyde undergoes cross aldol reaction with formaldehyde. The substrate are in 3:1 (HCHO:CH3CHO) ratio which will induce the mutiple enolate formation and corresponding aldol formations.