Question

Product of LCM and HCF of the two numbers=Product of the two numbers

Find the LCM of $8$ and $12$ and then find their HCF using the above relation.

Answer 1

We have given two digits $8$ and$12$

LCM of these two digits is the lowest common multiple of these two digits.

$8=8,16,24,32,40,48,56,64,72,80$ and

$12=12,24,36,48,60,72,84,96,108,120$

Thus we get $24$ is the lowest common multiple

Now,

HCF the highest factor of these two numbers is

$12=1,2,3,4,6,12$ and

$8=1,2,4,8$

Thus we get the highest common factor is $4$

so, The product of the LCM and HCF is

$24\times 4=96$

Now,

A/Q

The product of these two digits is:

$12\times 8=96$

Which shows the relation that product of the LCM and HCF is equal to the product of the numbers.