Question

Product of the following monomials 4p, – 7q³, –7pq$4p,–7q^3,–7pq$ is (a) $196p^2{q}^4$ (b) $196p{q}^4$ (c) $–196p^2{q}^4$ (d) $196p^2{q}^3$

Answer 1

Step 1. Determine the product of given monomials.

• A monomial is a number, a variable, or the product of two or more variables.
• When multiplying monomials, multiply the coefficients first, then the variables by adding the exponents.

$\begin{array}{rcl}4p·-7q^3·-7pq& =& \left(4·-7·-7\right)·\left(p·q^3·pq\right)\\ & =& 196\left(p^{1+1}{q}^{3+1}\right)[a^{m+n}=a^m·a^n]\\ & =& 196p^2{q}^4\end{array}$

Hence, the product of given polynomial is $196p^2{q}^4$. The correct option is (a)