Product of the following monomials 4p,−7q3,−7pq is a) 196p2q4 b) 196pq4 c) −196p2q4 d) 196p2q3
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Solution
a) 196p2q4 →Required product = 4p×(−7q3)×(−7pq) =4×(−7)×(−7)p×q3×pq [multiplying the numerical coefficients] =196p2q4 [multiplying the literal factors having same variables]