Question

Product of the following nuclear reaction is :

${}_5^{10}B{+}_2^{4}He⟶?{+}_0^{1}n$

• A. ${}_7^{13}N$
• B. ${}_7^{11}N$
• C. ${}_7^{14}N$
• D. None of these

Answer 1

The correct option is A ${}_7^{13}N$

The balanced reaction is as follows:

${}_5^{10}B{+}_2^{4}He{\to }_7^{13}N{+}_0^{1}n$