Product of the roots of the equation $x^{2} + 3 | x | - 28 = 0$ is

0

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- 16

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16

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- 28

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Solution

The correct option is D $- 16$
Consider the following question.

$x^{2} + 3 | x | - 28 = 0$

$x^{2} + 3 x - 28 = 0$

$x^{2} - 4 x + 7 x - 28 = 0$

$(x - 4) (x + 7)$

$= (- 4) \times 7$

The product of root eq. is = $- 28$

Hence, this is the required answer.

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