Product of the zeros of the cubic polynomial
$P (x) = k x^{3} - 5 x^{2} - 12 x + k$

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-1

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-2

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Solution

The correct option is B -1
Given polynomial
P(x) $= k x^{3} - 5 x^{2} - 12 x + k$
product of roots $a x^{3} + b x^{2} + c x + d = 0$
is $\frac{- d}{a}$
product of polynomials = $\frac{- k}{k} = - 1$

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Similar questions

If the sum of zeros of the polynomial p(x) = $k x^{3} - 5 x^{2} - 11 x - 3$ is 2, then k is equal to:

P (x) = 3 x^{3} - 5 x^{2} - 11 x - 3

\frac{- 1}{3}

a, - 1, - \frac{1}{a}

p (x) = 3 x^{3} - 5 x^{2} - 11 x - 3

p (x)

3, - 1, - \frac{1}{3}

p (x) = 3 x^{3} - 5 x^{2} - 11 x - 3

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