Products in this reaction will be :

Stereoisomers

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Enantiomers

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Diasteromers

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Geometrical isomers

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Solution

The correct options are
A Stereoisomers
C Diasteromers
D Geometrical isomers
Here first Ph- attacks on carbonyl group and an optically active compound forms as product.
So final products are geometrical isomers/ Stereoisomers/ Diasteromers.

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[C o C l_{2} (N H_{3})_{4}]^{+} + C l^{-} \to [C o C l_{3} (N H_{3})_{3}] + N H_{3}

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