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Hyperconjugation

Products is ...

Question

Products is $C i s - P h ({C H}_{3}) C = C H P h$ .
State whether the statement is true or false

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Solution

$(1 S, 2 S) - 1 - b r o m o p r o p a n e - 1, 2 - d i y l) d i b e n z e n e$ reacts with ethoxide ion to form $(Z) - p r o p - 1 - e n e - 1, 2 - d i y l d i b e n z e n e .$
Ethoxide ion is a strong base and affects dhydrobromination to form a carbon carbon double bond.
Anti elimination results in the formation of the cis alkene.

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