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Question

Products of ozonolysis of branched chain alkanes could be:

A
formaldehyde, acetaldehyde
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B
formaldehyde, 2-methylpropanal
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C
acetaldehyde, propanal
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D
acetaldehyde, acetone
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Solution

The correct options are
A formaldehyde, 2-methylpropanal
D acetaldehyde, acetone
Since the reactant is a branch chain alkane, thus the minimum number of carbon atoms must be 4, otherwise branching is not possible.
Thus the sum of the number of carbon atoms in the products should be greater than 4. Also if both products are aldehyde then one of them should have a branched chain. And if one is aldehyde and other ketones then there may or may not be a possibility of a branched chain in the product.
(A) The total number of carbon atoms less than four, hence incorrect.
(B) It could be a possible answer. as there is also 4 carbon in the products, hence correct.
(C) Both are aldehyde but none of them has branched chain, hence incorrect.
(D) This option is also correct as it fits the above-mentioned criteria, hence correct.

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