Question

Professor Burger has 27 chocolates with him. He wants to divide 27 chocolates equally among 6 children. How many would each child get?

• A. 3 $\frac{1}{2}$
• B. 4 $\frac{1}{2}$
• C. 4 $\frac{2}{1}$

Answer 1

The correct option is B 4 $\frac{1}{2}$

Total number of chocolates = 27
Number of children = 6
Number of chocolates given to each child = $\frac{27}{6}$
$\therefore \frac{27}{6}=\frac{3\times 3\times 3}{2\times 3}=\frac{3\times 3}{2}$
$=\frac{9}{2}$
$\frac{9}{2}\to$ nine-halves which is represented below:By looking at figure, We can see that each part is representing $\frac{1}{2}$ and there are 9 such halves.
If we join 2 halves to form 1 whole chocolate, then
we get 4 whole chocolates and $\frac{1}{2}$ of chocolates.

$\therefore \frac{9}{2}$ = 1 + 1 + 1 + 1 + $\frac{1}{2}$
= 4 $\frac{1}{2}$
Each child would recieve 4 $\frac{1}{2}$ pieces of chocolates.