Question

Progressive waves are represented by the equation $y_1=asin(\omega t-x)$ and $y_2=bcos(\omega t-x)$. The phase difference between waves is

• A. $0^o$
• B. ${45}^o$
• C. ${90}^o$
• D. ${180}^o$

Answer 1

Answer: (C)

${90}^o$

We know that $\sin (\theta +90°)=\cos \theta$

So, $y_2=b\cos (\omega t-x)=b\sin (\omega t-x+90°)$

Thus, the phase difference between the two waves is 90 degrees.