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Question

Projectile A is thrown horizontaly from tower of height H and projectile B is thrown from the ground at an angle θ as shown in the figure. During the duration when both are in air,


A
Path of A as seen by B will be a straight line
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B
Path of A as seen by B will be a parabola
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C
Motion of A is uniformly accelerated as seen by B.
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D
Relative acceleration of A with respect to B is zero
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Solution

The correct option is D Relative acceleration of A with respect to B is zero
Say,
rightside is positive x axis and
upwards is positive y axis.
VAB is velocity of A w.r.t. B.
VAB=VAVB
VA=VOAgt=VOA^igt^j .....(1)
VB=VOBgt=VOB cosθ^i+VOB sinθ^jgt^j ....(2)
VAB=(VOAVOBcosθ)^iVOBsin θ ^j
as we can see VAB is constant, and the relative acceleration between the bodies is zero. This implies, the path of the body is a straight line.

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