Projectile A is thrown horizontaly from tower of height H and projectile B is thrown from the ground at an angle θ as shown in the figure. During the duration when both are in air,
A
Path of A as seen by B will be a straight line
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B
Path of A as seen by B will be a parabola
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C
Motion of A is uniformly accelerated as seen by B.
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D
Relative acceleration of A with respect to B is zero
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Solution
The correct option is D Relative acceleration of A with respect to B is zero Say,
rightside is positive x axis and
upwards is positive y axis. VAB is velocity of A w.r.t. B. →VAB=→VA−→VB⇒ →VA=→VOA−→gt=VOA^i−gt^j .....(1) VB=→VOB−→gt=VOBcosθ^i+VOBsinθ^j−gt^j ....(2) →VAB=(VOA−VOBcosθ)^i−VOBsinθ^j
as we can see →VAB is constant, and the relative acceleration between the bodies is zero. This implies, the path of the body is a straight line.