Projection of A- along the vector B- is A- A-B-A-B-B-C- A- B - A -D- A - B - B

Given, nbsp;A and nbsp;B We know that the projection of A along B is given by A.B̂, where B̂ is the unit vector of B. So, we have B̂=B|B| Hence, projection ...

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Byju's Answer

Standard XII

Physics

Multiplication with Vectors

Projection of...

Question

Projection of $\to A$ along the vector $\to B$ is

\frac{\to A \cdot \to B}{| \to B |}

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\frac{\to A \times \to B}{| \to B |}

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\frac{\to A \cdot \to B}{| \to A |}

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\frac{\to A \cdot \to B}{\to B}

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Solution

The correct option is A $\frac{\to A \cdot \to B}{| \to B |}$
Given, $\to A$ and $\to B$
We know that the projection of $\to A$ along $\to B$ is given by $\to A .^B$ , where $^B$ is the unit vector of $\to B$ .
So, we have
$^B = \frac{\to B}{| \to B |}$
Hence, projection is given by
$\to A .^B = \frac{\to A \cdot \to B}{| \to B |}$

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Nonzero vectors $\to a, \to b, \to c$ satisfy $\to a . \to b$ =0, $(\to b - \to a) . (\to b + \to c)$ = 0 and 2 $| \to b + \to c | = | \to b - \to a |$ .