let 7+√5 be a rational no.
then 7+√5 = a/b , a and b are integers & b not equal to 0
√5 = (a/b)-7
√5=(a-7b)/b
√5= integer - 7 (integer)
Integer
=which is a rational no.
But √5 is irrational no.
So here it shows
LHS = Irrational and RHS = Rational
Therefore it is contradiction to our assumption
hence 7+√5 is irrational no.